The Newton's 3rd law explanation and the Bernoulli explanation are both reasonable approaches and both work, very similar to the way that one can explain the path of a thrown ball both by Newton's laws and by the principle of least action.
NASA has a good explanation here [1]. Here's a brief summary.
The gas flow has to simultaneously conserve mass, momentum, and energy.
If you analyze lift by considering conservation of momentum you get that there are velocity differences in the flow at different parts of the wing. Integrate those around the whole wing and you find a net turn of the flow downward. Conservation of momentum (Newton's 3rd) requires an opposite upward force on the wing.
If you analyze lift by considering conservation of energy you also get velocity differences which lead to pressure differences. Integrate pressure over the whole wing and you get a net upward force on the wing.
This doesn't really explain why those velocity variations occur in the first place, or am I missing something?
It sounds like "We observe velocity variations on the wing and these correspond to pressure variations that create lift due to conservation of energy." But it leaves the question on what is causing the velocity variations in the first place.
If you just mean there's a gravitational force on the Earth from the plane then, sure, but that's true for any object (including you and me). For an object on the ground, the normal force of that object on the ground balances their gravitational pull on the Earth, so the Earth experiences a net force of zero from the object and so isn't accelerated by it.
But I guess you mean that the plane has a net force pulling the earth towards it. But that would violate conservation of momentum – in fact the net force is zero, just as for an object on the ground. The plane's wings push the air down (the reaction to that is what keeps the plane up) and the resulting downdraft of that air exerts a force downwards on the earth.
That's all assuming the plane is in steady flight. If it's taking off, or just ascending, then overall it is pushing the Earth away from it. Conversely, when descending the Earth is pulled, overall, slightly towards it. The same thing happens when you jump: you push the Earth away from you (a much smaller distance than you travel away from it!), then on the way back down the Earth travels back towards you.
Crud I think you're right. I had it in my head that in steady flight, the plane had zero change in momentum, whereas, the air, collectively, gained net downward momentum. So to balance it all out, the earth must be gaining upward momentum (though of course spread over such an enormous mass as to make the velocity term imperceptible.)
NASA has a good explanation here [1]. Here's a brief summary.
The gas flow has to simultaneously conserve mass, momentum, and energy.
If you analyze lift by considering conservation of momentum you get that there are velocity differences in the flow at different parts of the wing. Integrate those around the whole wing and you find a net turn of the flow downward. Conservation of momentum (Newton's 3rd) requires an opposite upward force on the wing.
If you analyze lift by considering conservation of energy you also get velocity differences which lead to pressure differences. Integrate pressure over the whole wing and you get a net upward force on the wing.
[1] https://www1.grc.nasa.gov/beginners-guide-to-aeronautics/ber...